Base | Representation |
---|---|
bin | 1111101111111100010… |
… | …11100011000100110001 |
3 | 1220201202122122010001021 |
4 | 13313332023203010301 |
5 | 32331221122231423 |
6 | 1052332200335441 |
7 | 54044560412536 |
oct | 7677613430461 |
9 | 1821678563037 |
10 | 541135352113 |
11 | 199548887374 |
12 | 88a61174581 |
13 | 3c04b4ab105 |
14 | 1c2964d2d8d |
15 | e12213595d |
hex | 7dfe2e3131 |
541135352113 has 2 divisors, whose sum is σ = 541135352114. Its totient is φ = 541135352112.
The previous prime is 541135352101. The next prime is 541135352129. The reversal of 541135352113 is 311253531145.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 389715529984 + 151419822129 = 624272^2 + 389127^2 .
It is a cyclic number.
It is not a de Polignac number, because 541135352113 - 229 = 540598481201 is a prime.
It is not a weakly prime, because it can be changed into another prime (541135352213) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 270567676056 + 270567676057.
It is an arithmetic number, because the mean of its divisors is an integer number (270567676057).
Almost surely, 2541135352113 is an apocalyptic number.
It is an amenable number.
541135352113 is a deficient number, since it is larger than the sum of its proper divisors (1).
541135352113 is an equidigital number, since it uses as much as digits as its factorization.
541135352113 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 27000, while the sum is 34.
Adding to 541135352113 its reverse (311253531145), we get a palindrome (852388883258).
The spelling of 541135352113 in words is "five hundred forty-one billion, one hundred thirty-five million, three hundred fifty-two thousand, one hundred thirteen".
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