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5411413214443 = 17318318424379
BaseRepresentation
bin100111010111111000101…
…0111001100010011101011
3201011022210200122212022001
41032233301113030103223
51202130033240330233
615301545141311431
71065650602245625
oct116576127142353
921138720585261
105411413214443
1117a6a70758895
12734927405577
133033a9117222
14149cb165dc15
1595b6b0cd27d
hex4ebf15cc4eb

5411413214443 has 4 divisors (see below), whose sum is σ = 5729731638840. Its totient is φ = 5093094790048.

The previous prime is 5411413214429. The next prime is 5411413214479. The reversal of 5411413214443 is 3444123141145.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5411413214443 - 25 = 5411413214411 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5411413215443) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 159159212173 + ... + 159159212206.

It is an arithmetic number, because the mean of its divisors is an integer number (1432432909710).

Almost surely, 25411413214443 is an apocalyptic number.

5411413214443 is a deficient number, since it is larger than the sum of its proper divisors (318318424397).

5411413214443 is a wasteful number, since it uses less digits than its factorization.

5411413214443 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 318318424396.

The product of its digits is 92160, while the sum is 37.

Adding to 5411413214443 its reverse (3444123141145), we get a palindrome (8855536355588).

The spelling of 5411413214443 in words is "five trillion, four hundred eleven billion, four hundred thirteen million, two hundred fourteen thousand, four hundred forty-three".

Divisors: 1 17 318318424379 5411413214443