Base | Representation |
---|---|
bin | 100111010111111000111… |
… | …0010011000110000010001 |
3 | 201011022211012002001021021 |
4 | 1032233301302120300101 |
5 | 1202130042101441223 |
6 | 15301545554155441 |
7 | 1065651016656535 |
oct | 116576162306021 |
9 | 21138735061237 |
10 | 5411420343313 |
11 | 17a6a74787916 |
12 | 734929882b81 |
13 | 3033aa741caa |
14 | 149cb2597bc5 |
15 | 95b6ba3a65d |
hex | 4ebf1c98c11 |
5411420343313 has 2 divisors, whose sum is σ = 5411420343314. Its totient is φ = 5411420343312.
The previous prime is 5411420343311. The next prime is 5411420343383. The reversal of 5411420343313 is 3133430241145.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4077423063169 + 1333997280144 = 2019263^2 + 1154988^2 .
It is a cyclic number.
It is not a de Polignac number, because 5411420343313 - 21 = 5411420343311 is a prime.
Together with 5411420343311, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (5411420343311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2705710171656 + 2705710171657.
It is an arithmetic number, because the mean of its divisors is an integer number (2705710171657).
Almost surely, 25411420343313 is an apocalyptic number.
It is an amenable number.
5411420343313 is a deficient number, since it is larger than the sum of its proper divisors (1).
5411420343313 is an equidigital number, since it uses as much as digits as its factorization.
5411420343313 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 51840, while the sum is 34.
Adding to 5411420343313 its reverse (3133430241145), we get a palindrome (8544850584458).
The spelling of 5411420343313 in words is "five trillion, four hundred eleven billion, four hundred twenty million, three hundred forty-three thousand, three hundred thirteen".
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