Base | Representation |
---|---|
bin | 11000100110111101010101… |
… | …11101010101011110000011 |
3 | 21002121100200121220102121002 |
4 | 30103132222331111132003 |
5 | 24043110322224331442 |
6 | 311032054542522215 |
7 | 14253456066254051 |
oct | 1423365275253603 |
9 | 232540617812532 |
10 | 54115161167747 |
11 | 16274124777559 |
12 | 609ba69b9636b |
13 | 2427065086304 |
14 | d5128b3831d1 |
15 | 63c9d5da2732 |
hex | 3137aaf55783 |
54115161167747 has 2 divisors, whose sum is σ = 54115161167748. Its totient is φ = 54115161167746.
The previous prime is 54115161167701. The next prime is 54115161167779. The reversal of 54115161167747 is 74776116151145.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 54115161167747 - 220 = 54115160119171 is a prime.
It is a super-2 number, since 2×541151611677472 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 54115161167692 and 54115161167701.
It is not a weakly prime, because it can be changed into another prime (54115161167797) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27057580583873 + 27057580583874.
It is an arithmetic number, because the mean of its divisors is an integer number (27057580583874).
Almost surely, 254115161167747 is an apocalyptic number.
54115161167747 is a deficient number, since it is larger than the sum of its proper divisors (1).
54115161167747 is an equidigital number, since it uses as much as digits as its factorization.
54115161167747 is an evil number, because the sum of its binary digits is even.
The product of its digits is 4939200, while the sum is 56.
The spelling of 54115161167747 in words is "fifty-four trillion, one hundred fifteen billion, one hundred sixty-one million, one hundred sixty-seven thousand, seven hundred forty-seven".
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