Base | Representation |
---|---|
bin | 11000100110111101010101… |
… | …11101010101011101010101 |
3 | 21002121100200121220102112101 |
4 | 30103132222331111131111 |
5 | 24043110322224331301 |
6 | 311032054542522101 |
7 | 14253456066253654 |
oct | 1423365275253525 |
9 | 232540617812471 |
10 | 54115161167701 |
11 | 16274124777517 |
12 | 609ba69b96331 |
13 | 242706508629a |
14 | d5128b38319b |
15 | 63c9d5da2701 |
hex | 3137aaf55755 |
54115161167701 has 2 divisors, whose sum is σ = 54115161167702. Its totient is φ = 54115161167700.
The previous prime is 54115161167623. The next prime is 54115161167747. The reversal of 54115161167701 is 10776116151145.
It is an a-pointer prime, because the next prime (54115161167747) can be obtained adding 54115161167701 to its sum of digits (46).
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 53825684886801 + 289476280900 = 7336599^2 + 538030^2 .
It is a cyclic number.
It is not a de Polignac number, because 54115161167701 - 213 = 54115161159509 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54115161167201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27057580583850 + 27057580583851.
It is an arithmetic number, because the mean of its divisors is an integer number (27057580583851).
Almost surely, 254115161167701 is an apocalyptic number.
It is an amenable number.
54115161167701 is a deficient number, since it is larger than the sum of its proper divisors (1).
54115161167701 is an equidigital number, since it uses as much as digits as its factorization.
54115161167701 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 176400, while the sum is 46.
The spelling of 54115161167701 in words is "fifty-four trillion, one hundred fifteen billion, one hundred sixty-one million, one hundred sixty-seven thousand, seven hundred one".
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