Base | Representation |
---|---|
bin | 11000100111000111010111… |
… | …10111000100100100011111 |
3 | 21002121212120211120001111001 |
4 | 30103203223313010210133 |
5 | 24043202334010340444 |
6 | 311034345105211131 |
7 | 14254036362215014 |
oct | 1423435367044437 |
9 | 232555524501431 |
10 | 54120545011999 |
11 | 16276437815414 |
12 | 60a0b11030aa7 |
13 | 24277125baa7b |
14 | d5163c40170b |
15 | 63cbed87a8d4 |
hex | 3138ebdc491f |
54120545011999 has 4 divisors (see below), whose sum is σ = 54216673866936. Its totient is φ = 54024416157064.
The previous prime is 54120545011961. The next prime is 54120545012003. The reversal of 54120545011999 is 99911054502145.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 54120545011999 - 213 = 54120545003807 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (54120545011909) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 48064426624 + ... + 48064427749.
It is an arithmetic number, because the mean of its divisors is an integer number (13554168466734).
Almost surely, 254120545011999 is an apocalyptic number.
54120545011999 is a deficient number, since it is larger than the sum of its proper divisors (96128854937).
54120545011999 is an equidigital number, since it uses as much as digits as its factorization.
54120545011999 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 96128854936.
The product of its (nonzero) digits is 2916000, while the sum is 55.
The spelling of 54120545011999 in words is "fifty-four trillion, one hundred twenty billion, five hundred forty-five million, eleven thousand, nine hundred ninety-nine".
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