Base | Representation |
---|---|
bin | 11000100111001100010110… |
… | …11011111011111000101111 |
3 | 21002122010111102020222211222 |
4 | 30103212023123323320233 |
5 | 24043223324344044403 |
6 | 311035510503533555 |
7 | 14254162621331453 |
oct | 1423461333737057 |
9 | 232563442228758 |
10 | 54123222253103 |
11 | 16277590a77273 |
12 | 60a153975a2bb |
13 | 2427a4b1663c3 |
14 | d51813bcc663 |
15 | 63cd08917338 |
hex | 31398b6fbe2f |
54123222253103 has 2 divisors, whose sum is σ = 54123222253104. Its totient is φ = 54123222253102.
The previous prime is 54123222253049. The next prime is 54123222253183. The reversal of 54123222253103 is 30135222232145.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 54123222253103 - 26 = 54123222253039 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54123222253183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27061611126551 + 27061611126552.
It is an arithmetic number, because the mean of its divisors is an integer number (27061611126552).
Almost surely, 254123222253103 is an apocalyptic number.
54123222253103 is a deficient number, since it is larger than the sum of its proper divisors (1).
54123222253103 is an equidigital number, since it uses as much as digits as its factorization.
54123222253103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 86400, while the sum is 35.
Adding to 54123222253103 its reverse (30135222232145), we get a palindrome (84258444485248).
The spelling of 54123222253103 in words is "fifty-four trillion, one hundred twenty-three billion, two hundred twenty-two million, two hundred fifty-three thousand, one hundred three".
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