Base | Representation |
---|---|
bin | 100111011000010100101… |
… | …0010001010101101011001 |
3 | 201011102020002001201010011 |
4 | 1032300221102022231121 |
5 | 1202133443430440043 |
6 | 15302222214321521 |
7 | 1066013054003536 |
oct | 116605122125531 |
9 | 21142202051104 |
10 | 5412351421273 |
11 | 17a7402306535 |
12 | 734b496592a1 |
13 | 3034c85ca1b4 |
14 | 149d600c3d8d |
15 | 95bc365559d |
hex | 4ec2948ab59 |
5412351421273 has 2 divisors, whose sum is σ = 5412351421274. Its totient is φ = 5412351421272.
The previous prime is 5412351421271. The next prime is 5412351421307. The reversal of 5412351421273 is 3721241532145.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5397086324569 + 15265096704 = 2323163^2 + 123552^2 .
It is a cyclic number.
It is not a de Polignac number, because 5412351421273 - 21 = 5412351421271 is a prime.
Together with 5412351421271, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (5412351421271) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2706175710636 + 2706175710637.
It is an arithmetic number, because the mean of its divisors is an integer number (2706175710637).
Almost surely, 25412351421273 is an apocalyptic number.
It is an amenable number.
5412351421273 is a deficient number, since it is larger than the sum of its proper divisors (1).
5412351421273 is an equidigital number, since it uses as much as digits as its factorization.
5412351421273 is an evil number, because the sum of its binary digits is even.
The product of its digits is 201600, while the sum is 40.
The spelling of 5412351421273 in words is "five trillion, four hundred twelve billion, three hundred fifty-one million, four hundred twenty-one thousand, two hundred seventy-three".
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