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54125055503 = 431258722221
BaseRepresentation
bin110010011010000110…
…101100111000001111
312011201001211200222022
4302122012230320033
51341322003234003
640510435440355
73624161244431
oct623206547017
9164631750868
1054125055503
1120a55201332
12a5a64560bb
13514756847c
142896518651
15161babd738
hexc9a1ace0f

54125055503 has 4 divisors (see below), whose sum is σ = 55383777768. Its totient is φ = 52866333240.

The previous prime is 54125055493. The next prime is 54125055521. The reversal of 54125055503 is 30555052145.

54125055503 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 54125055503 - 24 = 54125055487 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (54125055563) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 629361068 + ... + 629361153.

It is an arithmetic number, because the mean of its divisors is an integer number (13845944442).

Almost surely, 254125055503 is an apocalyptic number.

54125055503 is a deficient number, since it is larger than the sum of its proper divisors (1258722265).

54125055503 is a wasteful number, since it uses less digits than its factorization.

54125055503 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1258722264.

The product of its (nonzero) digits is 75000, while the sum is 35.

The spelling of 54125055503 in words is "fifty-four billion, one hundred twenty-five million, fifty-five thousand, five hundred three".

Divisors: 1 43 1258722221 54125055503