Base | Representation |
---|---|
bin | 110010011010000110… |
… | …101100111000001111 |
3 | 12011201001211200222022 |
4 | 302122012230320033 |
5 | 1341322003234003 |
6 | 40510435440355 |
7 | 3624161244431 |
oct | 623206547017 |
9 | 164631750868 |
10 | 54125055503 |
11 | 20a55201332 |
12 | a5a64560bb |
13 | 514756847c |
14 | 2896518651 |
15 | 161babd738 |
hex | c9a1ace0f |
54125055503 has 4 divisors (see below), whose sum is σ = 55383777768. Its totient is φ = 52866333240.
The previous prime is 54125055493. The next prime is 54125055521. The reversal of 54125055503 is 30555052145.
54125055503 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 54125055503 - 24 = 54125055487 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (54125055563) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 629361068 + ... + 629361153.
It is an arithmetic number, because the mean of its divisors is an integer number (13845944442).
Almost surely, 254125055503 is an apocalyptic number.
54125055503 is a deficient number, since it is larger than the sum of its proper divisors (1258722265).
54125055503 is a wasteful number, since it uses less digits than its factorization.
54125055503 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1258722264.
The product of its (nonzero) digits is 75000, while the sum is 35.
The spelling of 54125055503 in words is "fifty-four billion, one hundred twenty-five million, fifty-five thousand, five hundred three".
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