Base | Representation |
---|---|
bin | 11000100111010010001000… |
… | …00111011001100011000101 |
3 | 21002122102111100110002120111 |
4 | 30103221010013121203011 |
5 | 24043301201041421113 |
6 | 311041142145233021 |
7 | 14254332453321001 |
oct | 1423510407314305 |
9 | 232572440402514 |
10 | 54126320654533 |
11 | 16278930a37106 |
12 | 60a2063332771 |
13 | 242812305192a |
14 | d51a294cb701 |
15 | 63ce3a94713d |
hex | 313a441d98c5 |
54126320654533 has 4 divisors (see below), whose sum is σ = 54126341975808. Its totient is φ = 54126299333260.
The previous prime is 54126320654489. The next prime is 54126320654557. The reversal of 54126320654533 is 33545602362145.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-54126320654533 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (54126320652533) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6242341 + ... + 12133402.
It is an arithmetic number, because the mean of its divisors is an integer number (13531585493952).
Almost surely, 254126320654533 is an apocalyptic number.
It is an amenable number.
54126320654533 is a deficient number, since it is larger than the sum of its proper divisors (21321275).
54126320654533 is a wasteful number, since it uses less digits than its factorization.
54126320654533 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21321274.
The product of its (nonzero) digits is 7776000, while the sum is 49.
The spelling of 54126320654533 in words is "fifty-four trillion, one hundred twenty-six billion, three hundred twenty million, six hundred fifty-four thousand, five hundred thirty-three".
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