Base | Representation |
---|---|
bin | 100111011000101011100… |
… | …1110100000010100011001 |
3 | 201011111012210102222210021 |
4 | 1032301113032200110121 |
5 | 1202142033241310040 |
6 | 15302430511150441 |
7 | 1066041133430263 |
oct | 116612716402431 |
9 | 21144183388707 |
10 | 5413122213145 |
11 | 17a7768407909 |
12 | 735123815421 |
13 | 3035bc1c466a |
14 | 149dd4608b33 |
15 | 95c1b15d24a |
hex | 4ec573a0519 |
5413122213145 has 8 divisors (see below), whose sum is σ = 6496098973056. Its totient is φ = 4330262892336.
The previous prime is 5413122213133. The next prime is 5413122213157.
5413122213145 is nontrivially palindromic in base 10.
It is an interprime number because it is at equal distance from previous prime (5413122213133) and next prime (5413122213157).
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5413122213145 - 213 = 5413122204953 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 5413122213145.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 29258337 + ... + 29442766.
It is an arithmetic number, because the mean of its divisors is an integer number (812012371632).
Almost surely, 25413122213145 is an apocalyptic number.
It is an amenable number.
5413122213145 is a deficient number, since it is larger than the sum of its proper divisors (1082976759911).
5413122213145 is a wasteful number, since it uses less digits than its factorization.
5413122213145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 58719551.
The product of its digits is 28800, while the sum is 34.
The spelling of 5413122213145 in words is "five trillion, four hundred thirteen billion, one hundred twenty-two million, two hundred thirteen thousand, one hundred forty-five".
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