541325001361241 has 4 divisors (see below), whose sum is σ = 541325375606400. Its totient is φ = 541324627116084.

The previous prime is 541325001361169. The next prime is 541325001361253. The reversal of 541325001361241 is 142163100523145.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 541325001361241 - 2¹⁰ = 541325001360217 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 541325001361195 and 541325001361204.

It is not an unprimeable number, because it can be changed into a prime (541325001321241) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 184944461 + ... + 187848618.

It is an arithmetic number, because the mean of its divisors is an integer number (135331343901600).

Almost surely, 2^{541325001361241} is an apocalyptic number.

It is an amenable number.

541325001361241 is a deficient number, since it is larger than the sum of its proper divisors (374245159).

541325001361241 is a wasteful number, since it uses less digits than its factorization.

541325001361241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 374245158.

The product of its (nonzero) digits is 86400, while the sum is 38.

Adding to 541325001361241 its reverse (142163100523145), we get a palindrome (683488101884386).

The spelling of 541325001361241 in words is "five hundred forty-one trillion, three hundred twenty-five billion, one million, three hundred sixty-one thousand, two hundred forty-one".