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54133540224037 is a prime number
BaseRepresentation
bin11000100111011111100100…
…11011110111110000100101
321002200010010111100020002121
430103233302123313300211
524043410442244132122
6311044334405505541
714255006406541411
oct1423576233676045
9232603114306077
1054133540224037
11162809a621a57a
1260a35391122b1
132428a039a4351
14d52112281d41
1563d20e683bc7
hex313bf26f7c25

54133540224037 has 2 divisors, whose sum is σ = 54133540224038. Its totient is φ = 54133540224036.

The previous prime is 54133540223969. The next prime is 54133540224097. The reversal of 54133540224037 is 73042204533145.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 52057177384356 + 2076362839681 = 7215066^2 + 1440959^2 .

It is a cyclic number.

It is not a de Polignac number, because 54133540224037 - 223 = 54133531835429 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 54133540223984 and 54133540224002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (54133540224097) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27066770112018 + 27066770112019.

It is an arithmetic number, because the mean of its divisors is an integer number (27066770112019).

Almost surely, 254133540224037 is an apocalyptic number.

It is an amenable number.

54133540224037 is a deficient number, since it is larger than the sum of its proper divisors (1).

54133540224037 is an equidigital number, since it uses as much as digits as its factorization.

54133540224037 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1209600, while the sum is 43.

The spelling of 54133540224037 in words is "fifty-four trillion, one hundred thirty-three billion, five hundred forty million, two hundred twenty-four thousand, thirty-seven".