Base | Representation |
---|---|
bin | 100111011000110101100… |
… | …0001011110101110111111 |
3 | 201011112001221101221102211 |
4 | 1032301223001132232333 |
5 | 1202143223302434403 |
6 | 15302523454001251 |
7 | 1066052305456222 |
oct | 116615301365677 |
9 | 21145057357384 |
10 | 5413454343103 |
11 | 17a7918936a84 |
12 | 7351b6aa6227 |
13 | 303642c61a71 |
14 | 14a0267835b9 |
15 | 95c3a3b706d |
hex | 4ec6b05ebbf |
5413454343103 has 8 divisors (see below), whose sum is σ = 5837357700720. Its totient is φ = 5003449456320.
The previous prime is 5413454343071. The next prime is 5413454343109. The reversal of 5413454343103 is 3013434543145.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5413454343103 - 25 = 5413454343071 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5413454343109) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3474616900 + ... + 3474618457.
It is an arithmetic number, because the mean of its divisors is an integer number (729669712590).
Almost surely, 25413454343103 is an apocalyptic number.
5413454343103 is a deficient number, since it is larger than the sum of its proper divisors (423903357617).
5413454343103 is a wasteful number, since it uses less digits than its factorization.
5413454343103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6949235417.
The product of its (nonzero) digits is 518400, while the sum is 40.
Adding to 5413454343103 its reverse (3013434543145), we get a palindrome (8426888886248).
The spelling of 5413454343103 in words is "five trillion, four hundred thirteen billion, four hundred fifty-four million, three hundred forty-three thousand, one hundred three".
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