Base | Representation |
---|---|
bin | 100111011000110111100… |
… | …1100000000110101101111 |
3 | 201011112020210212201001121 |
4 | 1032301233030000311233 |
5 | 1202143344144304403 |
6 | 15302534431321411 |
7 | 1066054114401646 |
oct | 116615714006557 |
9 | 21145223781047 |
10 | 5413524213103 |
11 | 17a7954319386 |
12 | 735216380267 |
13 | 303654586366 |
14 | 14a031b7035d |
15 | 95c415b93bd |
hex | 4ec6f300d6f |
5413524213103 has 16 divisors (see below), whose sum is σ = 5810535129600. Its totient is φ = 5030415963936.
The previous prime is 5413524212989. The next prime is 5413524213121. The reversal of 5413524213103 is 3013124253145.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5413524213103 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5413524213193) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4365453 + ... + 5466646.
It is an arithmetic number, because the mean of its divisors is an integer number (363158445600).
Almost surely, 25413524213103 is an apocalyptic number.
5413524213103 is a deficient number, since it is larger than the sum of its proper divisors (397010916497).
5413524213103 is a wasteful number, since it uses less digits than its factorization.
5413524213103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9832806.
The product of its (nonzero) digits is 43200, while the sum is 34.
Adding to 5413524213103 its reverse (3013124253145), we get a palindrome (8426648466248).
The spelling of 5413524213103 in words is "five trillion, four hundred thirteen billion, five hundred twenty-four million, two hundred thirteen thousand, one hundred three".
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