5413541441201 has 4 divisors (see below), whose sum is σ = 5588171810304. Its totient is φ = 5238911072100.

The previous prime is 5413541441197. The next prime is 5413541441219. The reversal of 5413541441201 is 1021441453145.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5413541441201 - 2² = 5413541441197 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (5413541441251) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 87315184505 + ... + 87315184566.

It is an arithmetic number, because the mean of its divisors is an integer number (1397042952576).

Almost surely, 2^{5413541441201} is an apocalyptic number.

It is an amenable number.

5413541441201 is a deficient number, since it is larger than the sum of its proper divisors (174630369103).

5413541441201 is a wasteful number, since it uses less digits than its factorization.

5413541441201 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 174630369102.

The product of its (nonzero) digits is 38400, while the sum is 35.

Adding to 5413541441201 its reverse (1021441453145), we get a palindrome (6434982894346).

The spelling of 5413541441201 in words is "five trillion, four hundred thirteen billion, five hundred forty-one million, four hundred forty-one thousand, two hundred one".