Base | Representation |
---|---|
bin | 11000100111101111011010… |
… | …01000100100110110001111 |
3 | 21002200221001221110021111201 |
4 | 30103313231020210312033 |
5 | 24044030400022324401 |
6 | 311052302123330331 |
7 | 14255430153011626 |
oct | 1423675510446617 |
9 | 232627057407451 |
10 | 54142041214351 |
11 | 16284568870402 |
12 | 60a51100809a7 |
13 | 2429759c5822c |
14 | d526bb2bc6bd |
15 | 63d55ab40b01 |
hex | 313ded224d8f |
54142041214351 has 2 divisors, whose sum is σ = 54142041214352. Its totient is φ = 54142041214350.
The previous prime is 54142041214309. The next prime is 54142041214381. The reversal of 54142041214351 is 15341214024145.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 54142041214351 - 27 = 54142041214223 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 54142041214351.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54142041214301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27071020607175 + 27071020607176.
It is an arithmetic number, because the mean of its divisors is an integer number (27071020607176).
Almost surely, 254142041214351 is an apocalyptic number.
54142041214351 is a deficient number, since it is larger than the sum of its proper divisors (1).
54142041214351 is an equidigital number, since it uses as much as digits as its factorization.
54142041214351 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 76800, while the sum is 37.
Adding to 54142041214351 its reverse (15341214024145), we get a palindrome (69483255238496).
The spelling of 54142041214351 in words is "fifty-four trillion, one hundred forty-two billion, forty-one million, two hundred fourteen thousand, three hundred fifty-one".
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