Base | Representation |
---|---|
bin | 110010011011000111… |
… | …110001011100000101 |
3 | 12011202020221100012111 |
4 | 302123013301130011 |
5 | 1341340340113131 |
6 | 40512245221021 |
7 | 3624456241345 |
oct | 623307613405 |
9 | 164666840174 |
10 | 54142113541 |
11 | 20a638a228a |
12 | a5b0101771 |
13 | 514ac5b799 |
14 | 28988b8d25 |
15 | 161d33cab1 |
hex | c9b1f1705 |
54142113541 has 2 divisors, whose sum is σ = 54142113542. Its totient is φ = 54142113540.
The previous prime is 54142113523. The next prime is 54142113607. The reversal of 54142113541 is 14531124145.
54142113541 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 46511392225 + 7630721316 = 215665^2 + 87354^2 .
It is a cyclic number.
It is not a de Polignac number, because 54142113541 - 231 = 51994629893 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54142113241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27071056770 + 27071056771.
It is an arithmetic number, because the mean of its divisors is an integer number (27071056771).
Almost surely, 254142113541 is an apocalyptic number.
It is an amenable number.
54142113541 is a deficient number, since it is larger than the sum of its proper divisors (1).
54142113541 is an equidigital number, since it uses as much as digits as its factorization.
54142113541 is an evil number, because the sum of its binary digits is even.
The product of its digits is 9600, while the sum is 31.
Adding to 54142113541 its reverse (14531124145), we get a palindrome (68673237686).
The spelling of 54142113541 in words is "fifty-four billion, one hundred forty-two million, one hundred thirteen thousand, five hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •