Base | Representation |
---|---|
bin | 11000100111110000000101… |
… | …01101000110110101101111 |
3 | 21002200222000011102121011120 |
4 | 30103320002231012311233 |
5 | 24044032120144043203 |
6 | 311052402052152023 |
7 | 14255442136051662 |
oct | 1423700255066557 |
9 | 232628004377146 |
10 | 54142403112303 |
11 | 16284734081720 |
12 | 60a51b1308613 |
13 | 24297b6c18b2c |
14 | d527133a56d9 |
15 | 63d57c7c9b53 |
hex | 313e02b46d6f |
54142403112303 has 32 divisors (see below), whose sum is σ = 79692065037312. Its totient is φ = 32424437635200.
The previous prime is 54142403112263. The next prime is 54142403112311. The reversal of 54142403112303 is 30321130424145.
It is not a de Polignac number, because 54142403112303 - 224 = 54142386335087 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (33).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (54142403112323) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 27930151 + ... + 29805672.
It is an arithmetic number, because the mean of its divisors is an integer number (2490377032416).
Almost surely, 254142403112303 is an apocalyptic number.
54142403112303 is a deficient number, since it is larger than the sum of its proper divisors (25549661925009).
54142403112303 is a wasteful number, since it uses less digits than its factorization.
54142403112303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 57736175.
The product of its (nonzero) digits is 34560, while the sum is 33.
Adding to 54142403112303 its reverse (30321130424145), we get a palindrome (84463533536448).
The spelling of 54142403112303 in words is "fifty-four trillion, one hundred forty-two billion, four hundred three million, one hundred twelve thousand, three hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.104 sec. • engine limits •