Base | Representation |
---|---|
bin | 1111110000011111111… |
… | …00010000100110000001 |
3 | 1220202112102100011112211 |
4 | 13320033330100212001 |
5 | 32332323413143040 |
6 | 1052421523222121 |
7 | 54055136256034 |
oct | 7701774204601 |
9 | 1822472304484 |
10 | 541433334145 |
11 | 199691002710 |
12 | 88b24b17941 |
13 | 3c098150542 |
14 | 1c2c3cdd01b |
15 | e13d3968ea |
hex | 7e0ff10981 |
541433334145 has 16 divisors (see below), whose sum is σ = 711726491520. Its totient is φ = 392135788800.
The previous prime is 541433334139. The next prime is 541433334179.
541433334145 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 541433334145 - 23 = 541433334137 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 541433334098 and 541433334107.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 20410485 + ... + 20436994.
It is an arithmetic number, because the mean of its divisors is an integer number (44482905720).
Almost surely, 2541433334145 is an apocalyptic number.
541433334145 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
It is an amenable number.
541433334145 is a deficient number, since it is larger than the sum of its proper divisors (170293157375).
541433334145 is a wasteful number, since it uses less digits than its factorization.
541433334145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 40847736.
The product of its digits is 518400, while the sum is 40.
It can be divided in two parts, 541433 and 334145, that added together give a palindrome (875578).
The spelling of 541433334145 in words is "five hundred forty-one billion, four hundred thirty-three million, three hundred thirty-four thousand, one hundred forty-five".
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