54143510003503 has 4 divisors (see below), whose sum is σ = 56993168424760. Its totient is φ = 51293851582248.

The previous prime is 54143510003501. The next prime is 54143510003519. The reversal of 54143510003503 is 30530001534145.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 54143510003503 - 2¹ = 54143510003501 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (54143510003501) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1424829210600 + ... + 1424829210637.

It is an arithmetic number, because the mean of its divisors is an integer number (14248292106190).

Almost surely, 2^{54143510003503} is an apocalyptic number.

54143510003503 is a deficient number, since it is larger than the sum of its proper divisors (2849658421257).

54143510003503 is a wasteful number, since it uses less digits than its factorization.

54143510003503 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2849658421256.

The product of its (nonzero) digits is 54000, while the sum is 34.

Adding to 54143510003503 its reverse (30530001534145), we get a palindrome (84673511537648).

The spelling of 54143510003503 in words is "fifty-four trillion, one hundred forty-three billion, five hundred ten million, three thousand, five hundred three".