Base | Representation |
---|---|
bin | 1111110000101000010… |
… | …00000100111110000001 |
3 | 1220202201022110001102012 |
4 | 13320110020010332001 |
5 | 32332444401303441 |
6 | 1052432512102305 |
7 | 54056651104064 |
oct | 7702410047601 |
9 | 1822638401365 |
10 | 541503541121 |
11 | 1997176a5204 |
12 | 88b44534995 |
13 | 3c0a986232a |
14 | 1c2cd3768db |
15 | e1446139eb |
hex | 7e14204f81 |
541503541121 has 2 divisors, whose sum is σ = 541503541122. Its totient is φ = 541503541120.
The previous prime is 541503541097. The next prime is 541503541123. The reversal of 541503541121 is 121145305145.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 309540900496 + 231962640625 = 556364^2 + 481625^2 .
It is a cyclic number.
It is not a de Polignac number, because 541503541121 - 26 = 541503541057 is a prime.
Together with 541503541123, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (541503541123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 270751770560 + 270751770561.
It is an arithmetic number, because the mean of its divisors is an integer number (270751770561).
Almost surely, 2541503541121 is an apocalyptic number.
It is an amenable number.
541503541121 is a deficient number, since it is larger than the sum of its proper divisors (1).
541503541121 is an equidigital number, since it uses as much as digits as its factorization.
541503541121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12000, while the sum is 32.
Adding to 541503541121 its reverse (121145305145), we get a palindrome (662648846266).
The spelling of 541503541121 in words is "five hundred forty-one billion, five hundred three million, five hundred forty-one thousand, one hundred twenty-one".
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