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54162063141 = 318054021047
BaseRepresentation
bin110010011100010011…
…110111111100100101
312011210122110212220120
4302130103313330211
51341410442010031
640514240552153
73625120640424
oct623423677445
9164718425816
1054162063141
1120a7408875a
12a5b6922659
135152124c94
14289b3cd2bb
15161ee7da96
hexc9c4f7f25

54162063141 has 4 divisors (see below), whose sum is σ = 72216084192. Its totient is φ = 36108042092.

The previous prime is 54162063139. The next prime is 54162063149. The reversal of 54162063141 is 14136026145.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 54162063141 - 21 = 54162063139 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (54162063149) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9027010521 + ... + 9027010526.

It is an arithmetic number, because the mean of its divisors is an integer number (18054021048).

Almost surely, 254162063141 is an apocalyptic number.

It is an amenable number.

54162063141 is a deficient number, since it is larger than the sum of its proper divisors (18054021051).

54162063141 is a wasteful number, since it uses less digits than its factorization.

54162063141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18054021050.

The product of its (nonzero) digits is 17280, while the sum is 33.

Adding to 54162063141 its reverse (14136026145), we get a palindrome (68298089286).

The spelling of 54162063141 in words is "fifty-four billion, one hundred sixty-two million, sixty-three thousand, one hundred forty-one".

Divisors: 1 3 18054021047 54162063141