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5417331981000 = 233536131919277
BaseRepresentation
bin100111011010101001000…
…1001011111101011001000
3201011220002011212100122020
41032311102021133223020
51202224143441343000
615304404333124440
71066250352033042
oct116652211375310
921156064770566
105417331981000
1117a95287457a5
12735ab9629720
13303b10410364
1414a2b3764a92
1595db5a1bba0
hex4ed5225fac8

5417331981000 has 256 divisors, whose sum is σ = 17186395000320. Its totient is φ = 1420341120000.

The previous prime is 5417331980987. The next prime is 5417331981031. The reversal of 5417331981000 is 1891337145.

It is a super-2 number, since 2×54173319810002 (a number of 26 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 583948362 + ... + 583957638.

It is an arithmetic number, because the mean of its divisors is an integer number (67134355470).

Almost surely, 25417331981000 is an apocalyptic number.

5417331981000 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 5417331981000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (8593197500160).

5417331981000 is an abundant number, since it is smaller than the sum of its proper divisors (11769063019320).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

5417331981000 is a wasteful number, since it uses less digits than its factorization.

5417331981000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12553 (or 12539 counting only the distinct ones).

The product of its (nonzero) digits is 90720, while the sum is 42.

The spelling of 5417331981000 in words is "five trillion, four hundred seventeen billion, three hundred thirty-one million, nine hundred eighty-one thousand".