Base | Representation |
---|---|
bin | 100111011011001111001… |
… | …1000111111110100110111 |
3 | 201012000101022210000020112 |
4 | 1032312132120333310313 |
5 | 1202234303421111041 |
6 | 15305135305253235 |
7 | 1066324143341456 |
oct | 116663630776467 |
9 | 21160338700215 |
10 | 5418611113271 |
11 | 17aa02478a804 |
12 | 7361b5a9421b |
13 | 303c8541cc65 |
14 | 14a3955b2b9d |
15 | 95e3ce88deb |
hex | 4ed9e63fd37 |
5418611113271 has 2 divisors, whose sum is σ = 5418611113272. Its totient is φ = 5418611113270.
The previous prime is 5418611113127. The next prime is 5418611113313. The reversal of 5418611113271 is 1723111168145.
Together with previous prime (5418611113127) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5418611113271 - 234 = 5401431244087 is a prime.
It is a super-2 number, since 2×54186111132712 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5418611115271) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2709305556635 + 2709305556636.
It is an arithmetic number, because the mean of its divisors is an integer number (2709305556636).
Almost surely, 25418611113271 is an apocalyptic number.
5418611113271 is a deficient number, since it is larger than the sum of its proper divisors (1).
5418611113271 is an equidigital number, since it uses as much as digits as its factorization.
5418611113271 is an evil number, because the sum of its binary digits is even.
The product of its digits is 40320, while the sum is 41.
The spelling of 5418611113271 in words is "five trillion, four hundred eighteen billion, six hundred eleven million, one hundred thirteen thousand, two hundred seventy-one".
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