Base | Representation |
---|---|
bin | 11000101001011101110011… |
… | …00011001011000010100101 |
3 | 21002220121001011022102222211 |
4 | 30110232321203023002211 |
5 | 24101013233130012240 |
6 | 311135422542523421 |
7 | 14262625605361633 |
oct | 1424567143130245 |
9 | 232817034272884 |
10 | 54201305313445 |
11 | 162a770a9081a4 |
12 | 60b46ab596571 |
13 | 24322130b61a4 |
14 | d55500130353 |
15 | 63ed7897dbea |
hex | 314bb98cb0a5 |
54201305313445 has 16 divisors (see below), whose sum is σ = 69587180599680. Its totient is φ = 40405459694400.
The previous prime is 54201305313431. The next prime is 54201305313451. The reversal of 54201305313445 is 54431350310245.
It is not a de Polignac number, because 54201305313445 - 221 = 54201303216293 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 54201305313398 and 54201305313407.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4676552041 + ... + 4676563630.
It is an arithmetic number, because the mean of its divisors is an integer number (4349198787480).
Almost surely, 254201305313445 is an apocalyptic number.
It is an amenable number.
54201305313445 is a deficient number, since it is larger than the sum of its proper divisors (15385875286235).
54201305313445 is a wasteful number, since it uses less digits than its factorization.
54201305313445 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9353115756.
The product of its (nonzero) digits is 432000, while the sum is 40.
The spelling of 54201305313445 in words is "fifty-four trillion, two hundred one billion, three hundred five million, three hundred thirteen thousand, four hundred forty-five".
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