Base | Representation |
---|---|
bin | 100111011100000010001… |
… | …0101101001100000001001 |
3 | 201012011210112012020102121 |
4 | 1032320010111221200021 |
5 | 1202301304301331213 |
6 | 15310021125131241 |
7 | 1066414422442153 |
oct | 116700425514011 |
9 | 21164715166377 |
10 | 5420321511433 |
11 | 17aa822205204 |
12 | 7365b2859b21 |
13 | 30419889a38a |
14 | 14a4b8803ad3 |
15 | 95edd1e388d |
hex | 4ee04569809 |
5420321511433 has 16 divisors (see below), whose sum is σ = 6060845782656. Its totient is φ = 4820884330240.
The previous prime is 5420321511401. The next prime is 5420321511461. The reversal of 5420321511433 is 3341151230245.
It is a cyclic number.
It is not a de Polignac number, because 5420321511433 - 25 = 5420321511401 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5420321511233) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 83477878 + ... + 83542783.
It is an arithmetic number, because the mean of its divisors is an integer number (378802861416).
Almost surely, 25420321511433 is an apocalyptic number.
It is an amenable number.
5420321511433 is a deficient number, since it is larger than the sum of its proper divisors (640524271223).
5420321511433 is a wasteful number, since it uses less digits than its factorization.
5420321511433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 167020784.
The product of its (nonzero) digits is 43200, while the sum is 34.
Adding to 5420321511433 its reverse (3341151230245), we get a palindrome (8761472741678).
The spelling of 5420321511433 in words is "five trillion, four hundred twenty billion, three hundred twenty-one million, five hundred eleven thousand, four hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •