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542034120433 = 13616710201843
BaseRepresentation
bin1111110001100111100…
…00000100111011110001
31220211002021211021101211
413320303300010323301
532340041213323213
61053001304200121
754106053001411
oct7706360047361
91824067737354
10542034120433
1119996a148303
1289072169041
133c162762ca0
141c33da0c641
15e175ebc53d
hex7e33c04ef1

542034120433 has 16 divisors (see below), whose sum is σ = 602153640256. Its totient is φ = 484791531840.

The previous prime is 542034120427. The next prime is 542034120443. The reversal of 542034120433 is 334021430245.

It is a happy number.

It is a cyclic number.

It is not a de Polignac number, because 542034120433 - 217 = 542033989361 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 542034120395 and 542034120404.

It is not an unprimeable number, because it can be changed into a prime (542034120413) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5047791 + ... + 5154052.

It is an arithmetic number, because the mean of its divisors is an integer number (37634602516).

Almost surely, 2542034120433 is an apocalyptic number.

It is an amenable number.

542034120433 is a deficient number, since it is larger than the sum of its proper divisors (60119519823).

542034120433 is a wasteful number, since it uses less digits than its factorization.

542034120433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10201984.

The product of its (nonzero) digits is 34560, while the sum is 31.

Adding to 542034120433 its reverse (334021430245), we get a palindrome (876055550678).

The spelling of 542034120433 in words is "five hundred forty-two billion, thirty-four million, one hundred twenty thousand, four hundred thirty-three".

Divisors: 1 13 61 67 793 871 4087 53131 10201843 132623959 622312423 683523481 8090061499 8885805253 41694932341 542034120433