54204332512738 has 4 divisors (see below), whose sum is σ = 81306498769110. Its totient is φ = 27102166256368.

The previous prime is 54204332512717. The next prime is 54204332512739. The reversal of 54204332512738 is 83721523340245.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 52300421001409 + 1903911511329 = 7231903^2 + 1379823^2 .

It is a junction number, because it is equal to n+sod(n) for n = 54204332512691 and 54204332512700.

It is not an unprimeable number, because it can be changed into a prime (54204332512739) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13551083128183 + ... + 13551083128186.

Almost surely, 2^{54204332512738} is an apocalyptic number.

54204332512738 is a deficient number, since it is larger than the sum of its proper divisors (27102166256372).

54204332512738 is a wasteful number, since it uses less digits than its factorization.

54204332512738 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 27102166256371.

The product of its (nonzero) digits is 4838400, while the sum is 49.

The spelling of 54204332512738 in words is "fifty-four trillion, two hundred four billion, three hundred thirty-two million, five hundred twelve thousand, seven hundred thirty-eight".