Base | Representation |
---|---|
bin | 11000101001100011011011… |
… | …11111000001010111100011 |
3 | 21002220212212010112002202012 |
4 | 30110301231333001113203 |
5 | 24101040433110401424 |
6 | 311141043202143135 |
7 | 14263063614216563 |
oct | 1424615577012743 |
9 | 232825763462665 |
10 | 54204332512739 |
11 | 162a8a236658a2 |
12 | 60b51b5351aab |
13 | 24325a6301986 |
14 | d5570a1b6da3 |
15 | 63eea45e6b0e |
hex | 314c6dfc15e3 |
54204332512739 has 2 divisors, whose sum is σ = 54204332512740. Its totient is φ = 54204332512738.
The previous prime is 54204332512717. The next prime is 54204332512747. The reversal of 54204332512739 is 93721523340245.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 54204332512739 - 236 = 54135613036003 is a prime.
It is not a weakly prime, because it can be changed into another prime (54204332532739) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27102166256369 + 27102166256370.
It is an arithmetic number, because the mean of its divisors is an integer number (27102166256370).
Almost surely, 254204332512739 is an apocalyptic number.
54204332512739 is a deficient number, since it is larger than the sum of its proper divisors (1).
54204332512739 is an equidigital number, since it uses as much as digits as its factorization.
54204332512739 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5443200, while the sum is 50.
The spelling of 54204332512739 in words is "fifty-four trillion, two hundred four billion, three hundred thirty-two million, five hundred twelve thousand, seven hundred thirty-nine".
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