Base | Representation |
---|---|
bin | 110010011110111000… |
… | …001011001010000001 |
3 | 12011220122112002020212 |
4 | 302132320023022001 |
5 | 1342003003232231 |
6 | 40522420043505 |
7 | 3626153014004 |
oct | 623670131201 |
9 | 164818462225 |
10 | 54205133441 |
11 | 20a96426048 |
12 | a609233595 |
13 | 515b025174 |
14 | 28a300153b |
15 | 1623b3a42b |
hex | c9ee0b281 |
54205133441 has 2 divisors, whose sum is σ = 54205133442. Its totient is φ = 54205133440.
The previous prime is 54205133431. The next prime is 54205133443. The reversal of 54205133441 is 14433150245.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 37614663025 + 16590470416 = 193945^2 + 128804^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-54205133441 is a prime.
Together with 54205133443, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 54205133398 and 54205133407.
It is not a weakly prime, because it can be changed into another prime (54205133443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27102566720 + 27102566721.
It is an arithmetic number, because the mean of its divisors is an integer number (27102566721).
Almost surely, 254205133441 is an apocalyptic number.
It is an amenable number.
54205133441 is a deficient number, since it is larger than the sum of its proper divisors (1).
54205133441 is an equidigital number, since it uses as much as digits as its factorization.
54205133441 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28800, while the sum is 32.
Adding to 54205133441 its reverse (14433150245), we get a palindrome (68638283686).
The spelling of 54205133441 in words is "fifty-four billion, two hundred five million, one hundred thirty-three thousand, four hundred forty-one".
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