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54210203150413 is a prime number
BaseRepresentation
bin11000101001101110010111…
…11001101110100001001101
321002221110000021011101200011
430110313023321232201031
524101134444001303123
6311143453514233221
714263362240631402
oct1424671371564115
9232843007141604
1054210203150413
111630046646a872
1260b6373425811
13243300064628b
14d55b05b502a9
156401e9bc9e0d
hex314dcbe6e84d

54210203150413 has 2 divisors, whose sum is σ = 54210203150414. Its totient is φ = 54210203150412.

The previous prime is 54210203150401. The next prime is 54210203150417. The reversal of 54210203150413 is 31405130201245.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 51733523530404 + 2476679620009 = 7192602^2 + 1573747^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-54210203150413 is a prime.

It is a super-2 number, since 2×542102031504132 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (54210203150417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27105101575206 + 27105101575207.

It is an arithmetic number, because the mean of its divisors is an integer number (27105101575207).

Almost surely, 254210203150413 is an apocalyptic number.

It is an amenable number.

54210203150413 is a deficient number, since it is larger than the sum of its proper divisors (1).

54210203150413 is an equidigital number, since it uses as much as digits as its factorization.

54210203150413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 54210203150413 its reverse (31405130201245), we get a palindrome (85615333351658).

The spelling of 54210203150413 in words is "fifty-four trillion, two hundred ten billion, two hundred three million, one hundred fifty thousand, four hundred thirteen".