5421524131141 has 4 divisors (see below), whose sum is σ = 5421675390784. Its totient is φ = 5421372871500.

The previous prime is 5421524131129. The next prime is 5421524131157. The reversal of 5421524131141 is 1411314251245.

5421524131141 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5421524131141 - 2¹¹ = 5421524129093 is a prime.

It is a super-3 number, since 3×5421524131141³ (a number of 39 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5421524131097 and 5421524131106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5421524135141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 75576045 + ... + 75647746.

It is an arithmetic number, because the mean of its divisors is an integer number (1355418847696).

Almost surely, 2^{5421524131141} is an apocalyptic number.

It is an amenable number.

5421524131141 is a deficient number, since it is larger than the sum of its proper divisors (151259643).

5421524131141 is a wasteful number, since it uses less digits than its factorization.

5421524131141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 151259642.

The product of its digits is 19200, while the sum is 34.

Adding to 5421524131141 its reverse (1411314251245), we get a palindrome (6832838382386).

The spelling of 5421524131141 in words is "five trillion, four hundred twenty-one billion, five hundred twenty-four million, one hundred thirty-one thousand, one hundred forty-one".