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542153553310471 = 1077150334560701
BaseRepresentation
bin111101101000101011111010…
…1111101010111001100000111
32122002121101002021222220012011
41323101113311331113030013
51032030120434121413341
65201021523135235051
7222124205313233464
oct17321276575271407
92562541067886164
10542153553310471
11147824037a255a3
1250980ba8078a87
131a368b25c8572b
1497c452ca5066b
1542a29d1114b81
hex1ed15f5f57307

542153553310471 has 4 divisors (see below), whose sum is σ = 542203887881944. Its totient is φ = 542103218739000.

The previous prime is 542153553310451. The next prime is 542153553310507. The reversal of 542153553310471 is 174013355351245.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 542153553310471 - 213 = 542153553302279 is a prime.

It is a super-3 number, since 3×5421535533104713 (a number of 45 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (542153553310451) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25167269580 + ... + 25167291121.

It is an arithmetic number, because the mean of its divisors is an integer number (135550971970486).

Almost surely, 2542153553310471 is an apocalyptic number.

542153553310471 is a deficient number, since it is larger than the sum of its proper divisors (50334571473).

542153553310471 is a wasteful number, since it uses less digits than its factorization.

542153553310471 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50334571472.

The product of its (nonzero) digits is 3780000, while the sum is 49.

The spelling of 542153553310471 in words is "five hundred forty-two trillion, one hundred fifty-three billion, five hundred fifty-three million, three hundred ten thousand, four hundred seventy-one".

Divisors: 1 10771 50334560701 542153553310471