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542171404452413 is a prime number
BaseRepresentation
bin111101101000110100001110…
…1111110000100001000111101
32122002200002011101001212100102
41323101220131332010020331
51032030414014014434123
65201034034343210445
7222125406553363211
oct17321503576041075
92562602141055312
10542171404452413
1114783066848576a
125098454a446a25
131a36a70c3c6b08
1497c53437ac941
1542a31c83b7028
hex1ed1a1df8423d

542171404452413 has 2 divisors, whose sum is σ = 542171404452414. Its totient is φ = 542171404452412.

The previous prime is 542171404452401. The next prime is 542171404452511. The reversal of 542171404452413 is 314254404171245.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 534855261255844 + 7316143196569 = 23126938^2 + 2704837^2 .

It is a cyclic number.

It is not a de Polignac number, because 542171404452413 - 28 = 542171404452157 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (542171404472413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 271085702226206 + 271085702226207.

It is an arithmetic number, because the mean of its divisors is an integer number (271085702226207).

Almost surely, 2542171404452413 is an apocalyptic number.

It is an amenable number.

542171404452413 is a deficient number, since it is larger than the sum of its proper divisors (1).

542171404452413 is an equidigital number, since it uses as much as digits as its factorization.

542171404452413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2150400, while the sum is 47.

The spelling of 542171404452413 in words is "five hundred forty-two trillion, one hundred seventy-one billion, four hundred four million, four hundred fifty-two thousand, four hundred thirteen".