Base | Representation |
---|---|
bin | 11000101010010101100001… |
… | …00111001010010001011111 |
3 | 21010000110020222022211111222 |
4 | 30111022300213022101133 |
5 | 24102011014323310012 |
6 | 311201251213203555 |
7 | 14265035122226066 |
oct | 1425126047122137 |
9 | 233013228284458 |
10 | 54231220135007 |
11 | 16309370a63423 |
12 | 60ba459a905bb |
13 | 2434c9c926b36 |
14 | d56b3b1251dd |
15 | 640a29d7e972 |
hex | 3152b09ca45f |
54231220135007 has 2 divisors, whose sum is σ = 54231220135008. Its totient is φ = 54231220135006.
The previous prime is 54231220134967. The next prime is 54231220135013. The reversal of 54231220135007 is 70053102213245.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 54231220135007 - 212 = 54231220130911 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54231220135607) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27115610067503 + 27115610067504.
It is an arithmetic number, because the mean of its divisors is an integer number (27115610067504).
Almost surely, 254231220135007 is an apocalyptic number.
54231220135007 is a deficient number, since it is larger than the sum of its proper divisors (1).
54231220135007 is an equidigital number, since it uses as much as digits as its factorization.
54231220135007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 50400, while the sum is 35.
The spelling of 54231220135007 in words is "fifty-four trillion, two hundred thirty-one billion, two hundred twenty million, one hundred thirty-five thousand, seven".
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