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542365444013 = 1493640036537
BaseRepresentation
bin1111110010001110111…
…11111110011110101101
31220211221101021020220112
413321013133332132231
532341231023202023
61053054221425405
754120215131361
oct7710737763655
91824841236815
10542365444013
1119a01a176648
128914510b265
133c1b62aa343
141c371a172a1
15e195117478
hex7e477fe7ad

542365444013 has 4 divisors (see below), whose sum is σ = 546005480700. Its totient is φ = 538725407328.

The previous prime is 542365443979. The next prime is 542365444031. The reversal of 542365444013 is 310444563245.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 347295705124 + 195069738889 = 589318^2 + 441667^2 .

It is a cyclic number.

It is not a de Polignac number, because 542365444013 - 28 = 542365443757 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (542365444073) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1820018120 + ... + 1820018417.

It is an arithmetic number, because the mean of its divisors is an integer number (136501370175).

Almost surely, 2542365444013 is an apocalyptic number.

It is an amenable number.

542365444013 is a deficient number, since it is larger than the sum of its proper divisors (3640036687).

542365444013 is a wasteful number, since it uses less digits than its factorization.

542365444013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3640036686.

The product of its (nonzero) digits is 691200, while the sum is 41.

The spelling of 542365444013 in words is "five hundred forty-two billion, three hundred sixty-five million, four hundred forty-four thousand, thirteen".

Divisors: 1 149 3640036537 542365444013