Base | Representation |
---|---|
bin | 11000101010101011111000… |
… | …00111010011010110100011 |
3 | 21010001121020120020002100022 |
4 | 30111111330013103112203 |
5 | 24102210110403121433 |
6 | 311210554311344055 |
7 | 14265641443544651 |
oct | 1425257407232643 |
9 | 233047216202308 |
10 | 54243224270243 |
11 | 16313470a89948 |
12 | 610084a08202b |
13 | 24361638a8938 |
14 | d575594dbdd1 |
15 | 640ecdb6a698 |
hex | 31557c1d35a3 |
54243224270243 has 2 divisors, whose sum is σ = 54243224270244. Its totient is φ = 54243224270242.
The previous prime is 54243224270189. The next prime is 54243224270311. The reversal of 54243224270243 is 34207242234245.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 54243224270243 - 28 = 54243224269987 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 54243224270194 and 54243224270203.
It is not a weakly prime, because it can be changed into another prime (54243224276243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27121612135121 + 27121612135122.
It is an arithmetic number, because the mean of its divisors is an integer number (27121612135122).
Almost surely, 254243224270243 is an apocalyptic number.
54243224270243 is a deficient number, since it is larger than the sum of its proper divisors (1).
54243224270243 is an equidigital number, since it uses as much as digits as its factorization.
54243224270243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2580480, while the sum is 44.
The spelling of 54243224270243 in words is "fifty-four trillion, two hundred forty-three billion, two hundred twenty-four million, two hundred seventy thousand, two hundred forty-three".
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