Base | Representation |
---|---|
bin | 110010100001100011… |
… | …011100100000100111 |
3 | 12012000210000010022201 |
4 | 302201203130200213 |
5 | 1342101001444033 |
6 | 40531102235331 |
7 | 3630236441050 |
oct | 624143344047 |
9 | 165023003281 |
10 | 54250031143 |
11 | 21009801390 |
12 | a620285b47 |
13 | 5167415059 |
14 | 28a8d6b727 |
15 | 1627a5847d |
hex | ca18dc827 |
54250031143 has 32 divisors (see below), whose sum is σ = 71220119040. Its totient is φ = 40034424960.
The previous prime is 54250031137. The next prime is 54250031189. The reversal of 54250031143 is 34113005245.
It is a cyclic number.
It is not a de Polignac number, because 54250031143 - 25 = 54250031111 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (54250031243) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 7213221 + ... + 7220737.
It is an arithmetic number, because the mean of its divisors is an integer number (2225628720).
Almost surely, 254250031143 is an apocalyptic number.
54250031143 is a deficient number, since it is larger than the sum of its proper divisors (16970087897).
54250031143 is a wasteful number, since it uses less digits than its factorization.
54250031143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12487.
The product of its (nonzero) digits is 7200, while the sum is 28.
Adding to 54250031143 its reverse (34113005245), we get a palindrome (88363036388).
The spelling of 54250031143 in words is "fifty-four billion, two hundred fifty million, thirty-one thousand, one hundred forty-three".
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