Base | Representation |
---|---|
bin | 100111011110010010011… |
… | …1111010111000101000111 |
3 | 201012122022000201120211002 |
4 | 1032330210333113011013 |
5 | 1202341214024043411 |
6 | 15312141442403515 |
7 | 1066645425356246 |
oct | 116744477270507 |
9 | 21178260646732 |
10 | 5425164284231 |
11 | 180188789407a |
12 | 73752466059b |
13 | 30478ac99603 |
14 | 14a817a5895d |
15 | 961c343e33b |
hex | 4ef24fd7147 |
5425164284231 has 2 divisors, whose sum is σ = 5425164284232. Its totient is φ = 5425164284230.
The previous prime is 5425164284201. The next prime is 5425164284383. The reversal of 5425164284231 is 1324824615245.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5425164284231 - 230 = 5424090542407 is a prime.
It is a super-2 number, since 2×54251642842312 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5425164284201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2712582142115 + 2712582142116.
It is an arithmetic number, because the mean of its divisors is an integer number (2712582142116).
Almost surely, 25425164284231 is an apocalyptic number.
5425164284231 is a deficient number, since it is larger than the sum of its proper divisors (1).
5425164284231 is an equidigital number, since it uses as much as digits as its factorization.
5425164284231 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1843200, while the sum is 47.
Adding to 5425164284231 its reverse (1324824615245), we get a palindrome (6749988899476).
The spelling of 5425164284231 in words is "five trillion, four hundred twenty-five billion, one hundred sixty-four million, two hundred eighty-four thousand, two hundred thirty-one".
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