Base | Representation |
---|---|
bin | 100111011110010100111… |
… | …0000101000111100101111 |
3 | 201012122111121022101101012 |
4 | 1032330221300220330233 |
5 | 1202341400020430333 |
6 | 15312153421535435 |
7 | 1066650416524403 |
oct | 116745160507457 |
9 | 21178447271335 |
10 | 5425244311343 |
11 | 1801918a8368a |
12 | 73754741457b |
13 | 3047a173912c |
14 | 14a82452b103 |
15 | 961ca49ae48 |
hex | 4ef29c28f2f |
5425244311343 has 2 divisors, whose sum is σ = 5425244311344. Its totient is φ = 5425244311342.
The previous prime is 5425244311309. The next prime is 5425244311381. The reversal of 5425244311343 is 3431134425245.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5425244311343 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 5425244311343.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5425244311393) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2712622155671 + 2712622155672.
It is an arithmetic number, because the mean of its divisors is an integer number (2712622155672).
Almost surely, 25425244311343 is an apocalyptic number.
5425244311343 is a deficient number, since it is larger than the sum of its proper divisors (1).
5425244311343 is an equidigital number, since it uses as much as digits as its factorization.
5425244311343 is an evil number, because the sum of its binary digits is even.
The product of its digits is 691200, while the sum is 41.
Adding to 5425244311343 its reverse (3431134425245), we get a palindrome (8856378736588).
The spelling of 5425244311343 in words is "five trillion, four hundred twenty-five billion, two hundred forty-four million, three hundred eleven thousand, three hundred forty-three".
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