Base | Representation |
---|---|
bin | 110010100001101111… |
… | …100100111000000111 |
3 | 12012000222222200110111 |
4 | 302201233210320013 |
5 | 1342102310224033 |
6 | 40531254333451 |
7 | 3630305454145 |
oct | 624157447007 |
9 | 165028880414 |
10 | 54253211143 |
11 | 2101058358a |
12 | a62135a287 |
13 | 5167c89601 |
14 | 28a9558595 |
15 | 1627e857cd |
hex | ca1be4e07 |
54253211143 has 2 divisors, whose sum is σ = 54253211144. Its totient is φ = 54253211142.
The previous prime is 54253211093. The next prime is 54253211161. The reversal of 54253211143 is 34111235245.
54253211143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-54253211143 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54253211183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27126605571 + 27126605572.
It is an arithmetic number, because the mean of its divisors is an integer number (27126605572).
Almost surely, 254253211143 is an apocalyptic number.
54253211143 is a deficient number, since it is larger than the sum of its proper divisors (1).
54253211143 is an equidigital number, since it uses as much as digits as its factorization.
54253211143 is an evil number, because the sum of its binary digits is even.
The product of its digits is 14400, while the sum is 31.
Adding to 54253211143 its reverse (34111235245), we get a palindrome (88364446388).
The spelling of 54253211143 in words is "fifty-four billion, two hundred fifty-three million, two hundred eleven thousand, one hundred forty-three".
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