Base | Representation |
---|---|
bin | 1111110011011111111… |
… | …01101010101111100011 |
3 | 1220220200200200112101022 |
4 | 13321233331222233203 |
5 | 32344123321104011 |
6 | 1053245432200055 |
7 | 54143100345362 |
oct | 7715775525743 |
9 | 1826620615338 |
10 | 543044316131 |
11 | 19a3383a5289 |
12 | 892b453902b |
13 | 3c293b2cb15 |
14 | 1c3d7c517d9 |
15 | e1d4a148db |
hex | 7e6ff6abe3 |
543044316131 has 2 divisors, whose sum is σ = 543044316132. Its totient is φ = 543044316130.
The previous prime is 543044316107. The next prime is 543044316167. The reversal of 543044316131 is 131613440345.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 543044316131 - 218 = 543044053987 is a prime.
It is a super-2 number, since 2×5430443161312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 543044316091 and 543044316100.
It is not a weakly prime, because it can be changed into another prime (543044396131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 271522158065 + 271522158066.
It is an arithmetic number, because the mean of its divisors is an integer number (271522158066).
Almost surely, 2543044316131 is an apocalyptic number.
543044316131 is a deficient number, since it is larger than the sum of its proper divisors (1).
543044316131 is an equidigital number, since it uses as much as digits as its factorization.
543044316131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 51840, while the sum is 35.
Adding to 543044316131 its reverse (131613440345), we get a palindrome (674657756476).
The spelling of 543044316131 in words is "five hundred forty-three billion, forty-four million, three hundred sixteen thousand, one hundred thirty-one".
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