Base | Representation |
---|---|
bin | 11000101100101100111111… |
… | …01110111001111101100111 |
3 | 21010022020011101111122010002 |
4 | 30112112133232321331213 |
5 | 24104324041040100203 |
6 | 311302500444451515 |
7 | 14303644256051663 |
oct | 1426263756717547 |
9 | 233266141448102 |
10 | 54312541331303 |
11 | 1633a901724872 |
12 | 6112174249b9b |
13 | 243c85c6a86b8 |
14 | d5aa5353b8a3 |
15 | 642bd9328d88 |
hex | 31659fbb9f67 |
54312541331303 has 2 divisors, whose sum is σ = 54312541331304. Its totient is φ = 54312541331302.
The previous prime is 54312541331261. The next prime is 54312541331311. The reversal of 54312541331303 is 30313314521345.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 54312541331303 - 214 = 54312541314919 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54312541331203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27156270665651 + 27156270665652.
It is an arithmetic number, because the mean of its divisors is an integer number (27156270665652).
Almost surely, 254312541331303 is an apocalyptic number.
54312541331303 is a deficient number, since it is larger than the sum of its proper divisors (1).
54312541331303 is an equidigital number, since it uses as much as digits as its factorization.
54312541331303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 194400, while the sum is 38.
Adding to 54312541331303 its reverse (30313314521345), we get a palindrome (84625855852648).
The spelling of 54312541331303 in words is "fifty-four trillion, three hundred twelve billion, five hundred forty-one million, three hundred thirty-one thousand, three hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.081 sec. • engine limits •