Base | Representation |
---|---|
bin | 110010100101010011… |
… | …101010101111101100 |
3 | 12012012011111110212012 |
4 | 302211103222233230 |
5 | 1342213112112022 |
6 | 40541232100352 |
7 | 3631632626321 |
oct | 624523525754 |
9 | 165164443765 |
10 | 54313004012 |
11 | 21041302883 |
12 | a6393946b8 |
13 | 51774931c7 |
14 | 28b3480b48 |
15 | 162d346de2 |
hex | ca54eabec |
54313004012 has 6 divisors (see below), whose sum is σ = 95047757028. Its totient is φ = 27156502004.
The previous prime is 54313003993. The next prime is 54313004027. The reversal of 54313004012 is 21040031345.
It is a super-2 number, since 2×543130040122 (a number of 22 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6789125498 + ... + 6789125505.
It is an arithmetic number, because the mean of its divisors is an integer number (15841292838).
Almost surely, 254313004012 is an apocalyptic number.
It is an amenable number.
54313004012 is a deficient number, since it is larger than the sum of its proper divisors (40734753016).
54313004012 is a wasteful number, since it uses less digits than its factorization.
54313004012 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13578251007 (or 13578251005 counting only the distinct ones).
The product of its (nonzero) digits is 1440, while the sum is 23.
Adding to 54313004012 its reverse (21040031345), we get a palindrome (75353035357).
The spelling of 54313004012 in words is "fifty-four billion, three hundred thirteen million, four thousand, twelve".
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