Base | Representation |
---|---|
bin | 1111110011110010100… |
… | …00000110000001110111 |
3 | 1220221002112220021111201 |
4 | 13321321100012001313 |
5 | 32344433214011211 |
6 | 1053313120113331 |
7 | 54150002006503 |
oct | 7717120060167 |
9 | 1827075807451 |
10 | 543200141431 |
11 | 19a408356122 |
12 | 89338765847 |
13 | 3c2ba1bb33c |
14 | 1c410815303 |
15 | e1e35450c1 |
hex | 7e79406077 |
543200141431 has 4 divisors (see below), whose sum is σ = 543611970000. Its totient is φ = 542788312864.
The previous prime is 543200141389. The next prime is 543200141441. The reversal of 543200141431 is 134141002345.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 543200141431 - 27 = 543200141303 is a prime.
It is a super-2 number, since 2×5432001414312 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 543200141431.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (543200141441) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 205912306 + ... + 205914943.
It is an arithmetic number, because the mean of its divisors is an integer number (135902992500).
Almost surely, 2543200141431 is an apocalyptic number.
543200141431 is a deficient number, since it is larger than the sum of its proper divisors (411828569).
543200141431 is a wasteful number, since it uses less digits than its factorization.
543200141431 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 411828568.
The product of its (nonzero) digits is 5760, while the sum is 28.
Adding to 543200141431 its reverse (134141002345), we get a palindrome (677341143776).
The spelling of 543200141431 in words is "five hundred forty-three billion, two hundred million, one hundred forty-one thousand, four hundred thirty-one".
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