Base | Representation |
---|---|
bin | 11000101101000101011011… |
… | …10011100001100010101011 |
3 | 21010100111000210222011121011 |
4 | 30112202231303201202223 |
5 | 24110032424023344112 |
6 | 311312510441124351 |
7 | 14304620361466441 |
oct | 1426425563414253 |
9 | 233314023864534 |
10 | 54325662324907 |
11 | 1634542512a536 |
12 | 61148164896b7 |
13 | 2440b70b6163c |
14 | d5b539da0b91 |
15 | 6432061caaa7 |
hex | 3168adce18ab |
54325662324907 has 2 divisors, whose sum is σ = 54325662324908. Its totient is φ = 54325662324906.
The previous prime is 54325662324859. The next prime is 54325662324919. The reversal of 54325662324907 is 70942326652345.
54325662324907 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 54325662324907 - 231 = 54323514841259 is a prime.
It is not a weakly prime, because it can be changed into another prime (54325662321907) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27162831162453 + 27162831162454.
It is an arithmetic number, because the mean of its divisors is an integer number (27162831162454).
Almost surely, 254325662324907 is an apocalyptic number.
54325662324907 is a deficient number, since it is larger than the sum of its proper divisors (1).
54325662324907 is an equidigital number, since it uses as much as digits as its factorization.
54325662324907 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 65318400, while the sum is 58.
The spelling of 54325662324907 in words is "fifty-four trillion, three hundred twenty-five billion, six hundred sixty-two million, three hundred twenty-four thousand, nine hundred seven".
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