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5433212112557 is a prime number
BaseRepresentation
bin100111100010000010010…
…1011011000111010101101
3201020102001220010121211212
41033010010223120322231
51203004204300100212
615315552211324205
71100352026650505
oct117040453307255
921212056117755
105433212112557
111805237659669
12738bab8b0665
133054713b74c8
1414ad7c812a05
15964e4c35e22
hex4f104ad8ead

5433212112557 has 2 divisors, whose sum is σ = 5433212112558. Its totient is φ = 5433212112556.

The previous prime is 5433212112527. The next prime is 5433212112563. The reversal of 5433212112557 is 7552112123345.

5433212112557 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5431109064676 + 2103047881 = 2330474^2 + 45859^2 .

It is a cyclic number.

It is not a de Polignac number, because 5433212112557 - 230 = 5432138370733 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5433212112527) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2716606056278 + 2716606056279.

It is an arithmetic number, because the mean of its divisors is an integer number (2716606056279).

Almost surely, 25433212112557 is an apocalyptic number.

It is an amenable number.

5433212112557 is a deficient number, since it is larger than the sum of its proper divisors (1).

5433212112557 is an equidigital number, since it uses as much as digits as its factorization.

5433212112557 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 252000, while the sum is 41.

The spelling of 5433212112557 in words is "five trillion, four hundred thirty-three billion, two hundred twelve million, one hundred twelve thousand, five hundred fifty-seven".