Base | Representation |
---|---|
bin | 11000101101010011101100… |
… | …11000001000110010100001 |
3 | 21010101012210122121220202101 |
4 | 30112221312120020302201 |
5 | 24110144121004131340 |
6 | 311320214513450401 |
7 | 14305311243465526 |
oct | 1426516630106241 |
9 | 233335718556671 |
10 | 54333322333345 |
11 | 163486a5a99220 |
12 | 61161b3870a01 |
13 | 24417c1b13c03 |
14 | d5ba6544514d |
15 | 643503917c9a |
hex | 316a76608ca1 |
54333322333345 has 32 divisors (see below), whose sum is σ = 71445298185216. Its totient is φ = 39338815723200.
The previous prime is 54333322333307. The next prime is 54333322333363.
54333322333345 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 54333322333345 - 29 = 54333322332833 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 54333322333295 and 54333322333304.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 9786762 + ... + 14298508.
It is an arithmetic number, because the mean of its divisors is an integer number (2232665568288).
Almost surely, 254333322333345 is an apocalyptic number.
54333322333345 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
It is an amenable number.
54333322333345 is a deficient number, since it is larger than the sum of its proper divisors (17111975851871).
54333322333345 is a wasteful number, since it uses less digits than its factorization.
54333322333345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4512741.
The product of its digits is 10497600, while the sum is 46.
It can be divided in two parts, 5433332 and 2333345, that added together give a palindrome (7766677).
The spelling of 54333322333345 in words is "fifty-four trillion, three hundred thirty-three billion, three hundred twenty-two million, three hundred thirty-three thousand, three hundred forty-five".
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