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543355344544013 = 693711178325883
BaseRepresentation
bin111101110001011011100011…
…0010011000110000100001101
32122020212021010012020002122122
41323202313012103012010031
51032204313221200402023
65203341555504222325
7222310061652202661
oct17342670623060415
92566767105202578
10543355344544013
11148147786828991
1250b35aa560a9a5
131a42525c6b1231
14982677900c8a1
1542c3dbd1c62c8
hex1ee2dc64c610d

543355344544013 has 4 divisors (see below), whose sum is σ = 543355429807008. Its totient is φ = 543355259281020.

The previous prime is 543355344543881. The next prime is 543355344544031. The reversal of 543355344544013 is 310445443553345.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 543355344544013 - 214 = 543355344527629 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (543355344544063) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32225831 + ... + 46100052.

It is an arithmetic number, because the mean of its divisors is an integer number (135838857451752).

Almost surely, 2543355344544013 is an apocalyptic number.

It is an amenable number.

543355344544013 is a deficient number, since it is larger than the sum of its proper divisors (85262995).

543355344544013 is an equidigital number, since it uses as much as digits as its factorization.

543355344544013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 85262994.

The product of its (nonzero) digits is 51840000, while the sum is 53.

The spelling of 543355344544013 in words is "five hundred forty-three trillion, three hundred fifty-five billion, three hundred forty-four million, five hundred forty-four thousand, thirteen".

Divisors: 1 6937111 78325883 543355344544013